InorgCh11.1

Report
A.
Electronic Spectra (Chapter 11 pp. 380-381)
1) A characteristic of transition metal complexes is color arising from
electronic transitions between d-orbitals of different energies
a) Everyday Examples of colored transition metal complexes
“Both rubies and sapphires owe
their intense colors to impurities,
ruby to the presence of chromium,
and blue sapphire to both titanium
and iron. In rubies, the color can
be explained by crystal field
theory, but in sapphire, a slightly
different process, known as charge
transfer, produces the color blue.”
http://www.webexhibits.org/causes
ofcolor/8.html
b)
The UV-Vis Experiment and the spectral result
2)
The Beer-Lambert Law
a) Absorbance = A = log (Io/I) Most modern systems give readings in A
directly, so you don’t have to do the math. A has no unit.
b)
A = elc describes the absorption of light in a solution
i.
l = the length of the cell containing the solution, usual 1 cm
ii. c = concentration in mol/L = M
iii. e = Molar extinction coefficient = constant for a given molecule at
a given wavelength of light = how well the molecule absorbs light
ε
3)
A
1

 M -1cm -1
lc (cm)(M)
Plotting Spectra
a) E = hn c = ln = 3 x 108 m/s
E
b)
h = 6.626 x 10-34 Js = Planck’s constant
hc
 energy of light of wavelength λ
λ
1
ν

 cm -1
Wavenumber =
λ
i. higher energy = larger wavenumbers
ii. Higher energy = smaller wavelength
500 nm  ?? cm -1
ν
1
 20,000 cm -1
-7
 10 cm 

(500nm)
nm


E
hc
 hcν
λ
4)
Color
a) What we see as the color of a compound is the complementary color to
what the compound absorbs
b) Example: Absorbs red, we see green
c) Example: Absorbs yellow/orange, we see blue/purple
d) Many complexes have multiple absorption band, so prediction is hard
B.
Interpreting the Electronic Spectrum of d1 Ti3+
1. Single d-electron species are relatively easy to understand
2.
Do can be calculated directly from the energy of light absorbed
 1  1nm 
1
Do  

  20,300cm
7
 493nm  1x10 cm 
C.
Interpreting the Spectra of Multi-Electron Species
1. Electron-Electron Interactions complicate the spectra of multi-electron species
2. Example: [V(H2O)6]3+ is an octahedral d2 metal ion
[V(H2O)6]3+
286nm
333nm
400nm
500nm
667nm
3.
Because of the multiple electrons, now we have multiple excited states
a)
b)
c)
d)
dxy1dxz1 is not the only possible ground state, but is convenient to use
We can promote one e- from dxy or dxz to dz2 or dx2-y2 (we show 2 above)
Excited states produced: dxy1dz21 and dxy1dx2-y21
The energy needed for this excitation is not the same for each: DEa ≠ DEb
dxy1dx2-y21 will be higher energy because more repulsion; both in xy plane
e)
4.
Excitation dxy1dxz1 ----> dxy2 = DEc
i. Energy change is for pairing the electrons
ii. Absorption is extremely week (“spin forbidden” to spin flip)
2+
[Mn(H2O)6]
Example: [Mn(H2O)6]2+
a) This spectrum has many very
weak; solution is very pale
b) Weak field ligand makes this a
high spin octahedral d5 metal ion
c) All possible transitions include
a “spin forbidden” spin flip, so all absorptions are very weak
5.
Example: [Cr(NH3)6]3+
a. There are two absorptions in its visible spectrum, one strong and one weak
b.
Explanation
i. Octahedral d3 metal ion has two types of excitations available
ii. One is “allowed”, the other spin forbidden
iii. Relatively strong field NH3 makes Do (450nm) > P (650nm)
6.
The Spectrochemical Series and Electronic Spectra of Metal Complexes
a) Ligand field strength affects Do, which effects the l of light absorbed
b)
c)
It is difficult to correlate color with ligand field strength due to multiple
absorbances of the multi-electron metal ions
A particular metal ion’s color may correlate with related ligands
NO2Cl-
I-
d)
Example: A sample of one Cr3+ complex is green and another is yellow.
One is [Cr(NH3)6]3+ and the other is [CrF6]3-. Which is which?
i. Determine the color of light absorbed to determine energy
ii. Green complex absorbs red (less energetic)
iii. Yellow complex absorbs blue (more energetic)
iv. NH3 complex must be yellow and F- complex must be green
e) Example: Assign the following two spectra to [Ni(H2O)6]2+ and [Ni(NH3)6]2+
and determine the color of their solutions.
i. NH3 is stronger field, so it should have higher energy peaks = (a)
ii. The NH3 complex absorbs all but ~750nm, so solution is red
iii. The H2O complex absorbs all but ~500nm, so solution is green = (b)
f) Example: A sample of one Co3+ complex is green and another is yellow.
One is [Co(F)6]3- and the other is [Cr(CN)6]3-. Which is which?
i. Green complex absorbs red (low energy) = F- complex (weak field)
ii. Yellow complex absorbs violet (high energy) = CN- complex (strong)

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