Report

© 2007 M. Tallman Imagine that you were able to take apart this rectangular prism so that all faces lay flat. It might look similar to this net. Examine the corresponding faces of the prism and the net. By counting all the square units in the net, you will find the surface area of the prism. How many units are there? 10 6 15 15 6 10 15 + 6 + 15 + 6 + 10 + 10 = 62 units² © 2007 M. Tallman Imagine that you were able to take apart this rectangular prism so that all faces lay flat. It might look similar to this net. Examine the corresponding faces of the prism and the net. By counting all the square units in the net, you will find the surface area of the prism. How many units are there? 9 9 9 9 9 9 9 + 9 + 9 + 9 + 9 + 9 = 54 units² © 2007 M. Tallman Imagine that you were able to take apart this rectangular prism so that all faces lay flat. It might look similar to this net. Examine the corresponding faces of the prism and the net. By counting all the square units in the net, you will find the surface area of the prism. How many units are there? 15 15 9 15 9 15 15 + 9 + 15 + 9 + 15 + 15 = 78 units² © 2007 M. Tallman Imagine that you were able to take apart this rectangular prism so that all faces lay flat. 6 ft 4 ft What are the measurements of the net? Find the area of each face? Then add the areas. 2 ft 2 ft 12 ft² 8 ft² Examine the corresponding faces of the prism and the net. 2 ft 6 ft 8 ft² It might look similar to this net. 4 ft 24 ft² 2 ft 12 ft² 4 ft 24 ft² 6 ft 2 ft 12 + 12 + 24 + 24 + 8 + 8 = 88 ft² © 2007 M. Tallman Keep in mind that you can only see 3 faces of this prism. Find the area for the visible faces of the prism using A = bh. Because there are 3 “non-visible” faces, double the 3 areas for the visible faces. Add all of the areas. 21 topm² 4 m 28 m² front 7 m 7 m × 4 m = 28 m² 7 m × 3 m = 21 m² 3 m × 4 m = 12 m² © 2007 M. Tallman right side 12 m² There are 3 other faces that are not visible. 3 m 56 m² 42 m² + 24 m² 122 m² Keep in mind that you can only see 3 faces of this prism. There are 3 other faces that are not visible. Find the area for the visible faces of the prism using A = bh. Because there are 3 “non-visible” faces, double the 3 areas for the visible faces. Add all of the areas. 5 m 4 m 20top m² 2 m front 10 m² 5 m × 2 m = 10 m² 5 m × 4 m = 20 m² 4 m × 2 m = 8 m² © 2007 M. Tallman 20 m² 40 m² + 16 m² 76 m² Find the surface area of the rectangular prism. front face: 5 × ___ 6 = ___ 30 units² ___ back face: 5 × ___ 6 = ___ 30 units² ___ top face: 5 × ___ 7 = ___ 35 units² ___ 5 × ___ 7 = ___ 35 units² bottom face: ___ left face: 7 × ___ 6 = ___ 42 units² ___ 7 × ___ 6 = ___ 42 units² ___ 214 units² Total Surface Area: + ___ right face: © 2007 M. Tallman Find the surface area of the rectangular prism. 2 ft 3 ft 7 ft front face: 3 × ___ 7 = ___ 21 ft² ___ back face: 3 × ___ 7 = ___ 21 ft² ___ top face: 3 × ___ 2 = ___ 6 ft² ___ 3 × ___ 2 = ___ 6 ft² bottom face: ___ right face: 2 × ___ 7 = ___ 14 ft² ___ 2 × ___ 7 = ___ 14 ft² ___ 82 ft² Total Surface Area: + ___ left face: © 2007 M. Tallman Find the surface area of the rectangular prism. front face: 12 × ___ 9 = 108 ___ ___ m² back face: 12 × ___ 9 = 108 ___ ___ m² top face: 12 × ___ 8 = ___ 96 m² ___ 12 × ___ 8 = ___ 96 m² bottom face: ___ 9 m 12 m 8 m right face: 8 × ___ 9 = ___ 72 m² ___ left face: 8 × ___ 9 = ___ 72 m² ___ Total Surface Area: © 2007 M. Tallman 552 m² + ___ Find the surface area of the rectangular prism. 7 m 11 m front face: 11 × ___ 4 = ___ 44 m² ___ back face: 11 × ___ 4 = ___ 44 m² ___ 4 m top face: bottom face: right face: 11 × ___ 7 = ___ 77 m² ___ 11 × ___ 7 = ___ 77 m² ___ 7 × ___ 4 = ___ 28 m² ___ 7 × ___ 4 = ___ 28 m² ___ Total Surface Area: + 298 ___ m² left face: © 2007 M. Tallman Find the surface area of this net. 8 m 8 m × 5 m = 40 m² 2 m × 5 m = 10 m² 5 m 2 m × 5 m = 10 m² 2 m 8 m × 2 m = 16 m² 2 m 5 m 2 m 8 m × 2 m = 16 m² 2 m 5 m 8 m × 5 m = 40 m² 5 m 8 m 16 m² + 16 m² + 40 m²+ 40 m² + 10 m² + 10 m² = 132 m² © 2007 M. Tallman 3 in 6 in 3 in 6 in × 10 in = 60 in² 3 in × 10 in = 30 in² 10 in 3 in × 10 in = 30 in² Find the surface area of this net. 6 in × 3 in = 3 in 18 in² 6 in × 3 in = 18 in² 3in 6 in × 10 in = 60 in² 10 in 6 in 30 in² + 30 in²+ 60 in²+ 60 in² + 18 in² + 18 in² = 216 in² © 2007 M. Tallman