Slide 1

Report
MR G’s Water Rocket experiment
3. Maximum
Gravitational
Potential energy
2. Maximum
Kinetic
energy
1. Maximum
Strain Potential
energy
4. Maximum
Kinetic
energy
“ROCKET SCIENCE”
500g water
5 m/s
100g Rocket
? m/s
“ROCKET SCIENCE”
100g Rocket
500g water
? m/s
5 m/s
Momentum of exhaust
=
Momentum of Rocket
“ROCKET SCIENCE”
100g Rocket
500g water
? m/s
5 m/s
Momentum of exhaust
Mass of water x velocity of water
=
=
Momentum of Rocket
Mass of Rocket x velocity of Rocket
“ROCKET SCIENCE”
100g Rocket
500g water
? m/s
5 m/s
Momentum of exhaust
Mass of water x velocity of water
0.5 Kg x 5 m/s
=
=
=
Momentum of Rocket
Mass of Rocket x velocity of Rocket
0.10 Kg x VR
“ROCKET SCIENCE”
100g Rocket
500g water
? m/s
5 m/s
Momentum of exhaust
Mass of water x velocity of water
0.5 Kg x 5 m/s
=
Momentum of Rocket
=
=
0.5 Kg x 5 m/s =
0.10
Mass of Rocket x velocity of Rocket
0.10 Kg x VR
VR
“ROCKET SCIENCE”
100g Rocket
500g water
? m/s
5 m/s
Momentum of exhaust
Mass of water x velocity of water
0.5 Kg x 5 m/s
=
Momentum of Rocket
=
=
0.5 Kg x 5 m/s =
0.10
Mass of Rocket x velocity of Rocket
0.10 Kg x VR
VR
VR = 25 m/s
“ROCKET SCIENCE”
100g Rocket
500g water
? m/s
5 m/s
Momentum of exhaust
Mass of water x velocity of water
0.5 Kg x 5 m/s
=
Momentum of Rocket
=
=
0.5 Kg x 5 m/s =
0.10
Mass of Rocket x velocity of Rocket
0.10 Kg x VR
VR
VR = 25 m/s
= 56 mph
“ROCKET SCIENCE”
V = 0 m/s
a = - 10 m/s/s
uR = 25 m/s
Maximum height ?
( ignore drag forces)
“ROCKET SCIENCE”
V = 0 m/s
a = - 10 m/s/s
Maximum height ?
( ignore drag forces)
a =
uR = 25 m/s
v–u
t
“ROCKET SCIENCE”
V = 0 m/s
a = - 10 m/s/s
Maximum height ?
( ignore drag forces)
a =
v–u
t
t =
v–u
a
uR = 25 m/s
Flight time:
“ROCKET SCIENCE”
V = 0 m/s
a = - 10 m/s/s
Maximum height ?
( ignore drag forces)
a =
v–u
t
t =
v–u
a
uR = 25 m/s
Flight time:
t =
0 – 25
-10
= 2.5 sec
“ROCKET SCIENCE”
V = 0 m/s
a = - 10 m/s/s
Maximum height ?
( ignore drag forces)
a =
v–u
t
t =
v–u
a
uR = 25 m/s
Flight time:
Velocity
m/s
time/s
t =
0 – 25
-10
= 2.5 sec
“ROCKET SCIENCE”
V = 0 m/s
Maximum height ?
( ignore drag forces)
a = - 10 m/s/s
a =
v–u
t
t =
v–u
a
uR = 25 m/s
Flight time:
Velocity
m/s
25 m/s
2.5 s
time/s
t =
0 – 25
-10
= 2.5 sec
“ROCKET SCIENCE”
V = 0 m/s
Maximum height ?
( ignore drag forces)
a = - 10 m/s/s
a =
v–u
t
t =
v–u
a
uR = 25 m/s
Flight time:
t =
0 – 25
-10
= 2.5 sec
Velocity
m/s
25 m/s
Area = distance travelled = 2.5 x 25
2
2.5 s
time/s
“ROCKET SCIENCE”
V = 0 m/s
Maximum height ?
( ignore drag forces)
a = - 10 m/s/s
a =
v–u
t
t =
v–u
a
uR = 25 m/s
Flight time:
t =
0 – 25
-10
= 2.5 sec
Velocity
m/s
25 m/s
Area = distance travelled = 2.5 x 25
2
2.5 s
time/s
“ROCKET SCIENCE”
V = 0 m/s
Maximum height ?
( ignore drag forces)
a = - 10 m/s/s
a =
v–u
t
t =
v–u
a
uR = 25 m/s
Flight time:
t =
0 – 25
-10
= 2.5 sec
Velocity
m/s
25 m/s
Area = distance travelled = 2.5 x 25
2
Maximum height reached = 31.25 m
2.5 s
time/s

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