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8. BC = ED = 4; BC = EC = 3; DC = DC by Reflex so ΔBCD ΔEDC by SSS 9. KJ = LJ; GK = GL; GJ = GJ by Reflex so ΔGJK ΔGJL by SSS 12. YZ = 24, ST = 20, SU = 22 so XY = ST, YZ = TU, XZ = SU so ΔXYZ ΔSTU by SSS 13. Given DB = CB AB DC Def of Rt Thm AB = AB SAS 14. SAS 15. SAS 16. Neither 17. Neither 18. To use SSS, need AB = DE and CB = CE To use SAS, need CB = CE 20. AB = √17, BC = 5, AC = √26, DE = √17, EF = 5, DF = 4, Δs not 21. Given Def of mWVY mZYV Def of Given VY = VY SAS 23. Check drawings ex. 7-7-1 and 6-6-3 24. X = 5.5, AB = BD, BC = DC (def of ), AC = AC (reflex), so ΔABC ΔADC by SSS 42. 86 43. 34° 44. 70° Warm Up 1. What are sides AC and BC called? Side AB? legs; hypotenuse 2. Which side is in between A and C? AC 3. Given DEF and GHI, if D G and E H, why is F I? Third s Thm. An included side is the common side of two consecutive angles in a polygon. The following postulate uses the idea of an included side. Example 2A: Determine if you can use ASA to prove the triangles congruent. Explain. Two congruent angle pairs are give, but the included sides are not given as congruent. Therefore ASA cannot be used to prove the triangles congruent. Example 2B: Determine if you can use ASA to prove NKL LMN. Explain. By the Alternate Interior Angles Theorem. KLN MNL. NL LN by the Reflexive Property. No other congruence relationships can be determined, so ASA cannot be applied. You can use the Third Angles Theorem to prove another congruence relationship based on ASA. This theorem is Angle-Angle-Side (AAS). AAS using only steps 1 and 3 Example 3: Use AAS to prove the triangles congruent. Given: X V, YZW YWZ, XY VY Prove: XYZ VYW Statements Reasons 1. X V 1. Given 2. YZW YWZ 2. Given 3. XY VY 3. 4. XYZ VYW 4. Given AAS Example 4A: Determine if you can use the HL Congruence Theorem to prove the triangles congruent. If not, tell what else you need to know. According to the diagram, the triangles are right triangles that share one leg. It is given that the hypotenuses are congruent, therefore the triangles are congruent by HL. This conclusion cannot be proved by HL. According to the diagram, the triangles are right triangles and one pair of legs is congruent. You do not know that one hypotenuse is congruent to the other. Example 4 Determine if you can use the HL Congruence Theorem to prove ABC DCB. If not, tell what else you need to know. Yes; it is given that AC DB. BC CB by the Reflexive Property of Congruence. Since ABC and DCB are right angles, ABC and DCB are right triangles. ABC DCB by HL.