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Part 6 - Power …the rate at which energy is converted. …the rate at which work is done. …P …measured in Watts (W), which is J/s. P = ΔE/t P = W/t ◦ But, W = FΔx, so P = FΔx/t ◦ And Δx/t = v, so P = Fv ΔE = change in energy t = time W = work F = force Δx = displacement v = velocity Defined by James Watt: ◦ The amount of work a horse can do in one second. ◦ One horsepower = 746 Watts A 50.0 kg student climbs 5.00 m up a rope at a constant speed. if the student's power output is 200.0 W, how long does it take the student to climb the rope? How much work does he do? P = FΔx/t m=50 kg Pt = FΔx Δx=5 m 200t = (490*5) P=200 W 200t = (2450) t=? t = (2450)/200 F=? W = FΔx t = 12.25 s W=? W = (490)(5) W = 2,450 J