Slide 1

Report
18
Weight (lbs.)
15
12
9
6
3
2
4
6
8
10
Age (months)
This is a LINE GRAPH. It’s easy to see the
baby’s weight changing as the months go by.
Since Jill charges $25 per lawn each time,
the “25” will not have a variable next to it.
$18 for each hour means that the “18”
should be multiplied by the “h”.
Then, we simply add the 18h and the 25
together to get the total charge.
Since all right angles must be 90o,
the yellow angle is also 45o.
Even though Leroy has rolled
a “5” four times in a row,
that won’t affect the
probability of his next toss.
The cube has 6 sides. Each side is equally
likely to land facing up. The probability of
any number being rolled is 1/6.
Each can is a cylinder.
Volume = p * r2 * h
Volume = p * (1)2
2”
4”
5
Volume = 5p in3
5”
cola
*
10”
The volume of the juice can is
8 times greater than the
volume of the cola can.
Volume = p * (2)2
*
10
Volume = 40p in3
juice
When writing a number in scientific notation, you slip the
decimal point in so that you’ve got a number between 1 and 10.
Next, you see how far the decimal point needs to be moved in
order to get it back to where it’s supposed to be. (Since we’re
moving it to the LEFT, the exponent will be NEGATIVE.)
When the shape is folded, these two
segments will be joined together.
Therefore, the circles and squares
will need to be next to each other.
500 boxes total
35
boxes
Each day, he loses 35 boxes.
35
boxes
35
boxes
The area of this triangle = ½(3)(2)
= 3 cm2
Since there are four
identical triangles, their
combined area is 12 cm2.
The red rectangle is 6 cm x 3 cm,
so its area is 18 cm2.
The total area of the hexagon is
12 cm2 + 18 cm2 = 30 cm2.
Since Pedro actually made more
money, the group’s mean will increase.
The nice thing about this problem is
that you don’t have to add all the
numbers together to solve it.
Once the mistake was fixed,
Pedro had earned an extra $16.
Since there are 8 people in the
group, that means we could simply
take 16  8 to find how much the
group’s mean increases by.
If we multiply each number in the first
column by 2, we’re always slightly too large.
Subtracting 1 fixes this problem each time.
Therefore, our formula for figure “n” is
2n-1 shaded squares.
Notice how the numbers on the left side
of the table go up by one, while the numbers
on the right side go up by two each time.
This tells us that the formula for finding
the number of shaded squares must involve
multiplication by 2.
Figure
Shaded
Squares
1
1
2
3
3
5
4
7
5
9
6
11
7
13
n
2n-1
= 2(50) - 1
= 99 shaded squares
Figure
Shaded
Squares
1
1
2
3
3
5
4
7
5
9
6
11
7
13
n
2n-1
50
99
Let’s convert them all to decimals…
7.75
7.625
7.071
7.82
Now, arrange them from
least to greatest…
7.071
7.625
7.75
7.82
First, convert 18o C to Fahrenheit.
F = (9/5)(18) + 32
F = 32.4 + 32
F = 64.4o
The difference between high
and low temperatures can be
found by subtracting.
64.4o - 44.6o
19.8o F
Next, convert 7o C to Fahrenheit.
F = (9/5)(7) + 32
F = 12.6 + 32
F = 44.6o
Add
Add
Add
Add
6
21
7
28
8
36
9
45
10
55
2
3
4
5
If we continue this pattern,
here’s what the table would
look like…
Other students may prefer
to work with formulas.
The number of cans can be
found by using the formula
( L )( L+1 )
2
For example…
6
21
7
28
8
36
( 4 )( 4+1 )
9
45
10
55
2
( 7 )( 7+1 )
2
( 10 )( 10+1 )
2
=
=
=
( 4 )( 5 )
2
( 7 )( 8 )
2
( 10 )( 11 )
2
= 10
= 28
= 55
The residents’
concern is about the
traffic volume during
the 4-6 PM rush
hour period only.
It’s very possible that
this intersection may
not be used much at all
during the rest of the
day, so including nonrush hour data will
make the intersection
seem less busy.
The department could get
more accurate data if
they would only monitor
the intersection between
4-6 PM instead of taking
an overall daily average.
Parallel lines have the
same slope.
The slope of RW is ¼.
Going up 1 block and over
4 blocks from point Q
puts us at (-1,-3).
(As you can see, we’ve
formed a parallelogram.)
h
0.4 meters
1.5 meters
Volume = (length)(width)(height)
0.75 = (1.5)(0.4)(height)
0.75 = (0.6)(height)
0.6
0.6
height = 1.25 meters
The best way is to try
each formula to see
whether or not it works.
As luck would have it, choice
A works all four times, so
it’s the right answer.
1.15 (3) = 3.45
1.15 (5) = 5.75
1.15 (8) = 9.20
1.15 (12) = 13.80
If choice A would have failed, we would have gone to choice B,
then choice C, etc. The correct answer must work all 4 times.
(3)(5)(4) = 60 different meals
First, make a proportion.
Include units before you start.
50
7.5
meters
kg
=
x
502.5
Next, cross-multiply and solve using Algebra.
(7.5)(x) = (50)(502.5)
7.5x = 25125
x = 3350
meters
kg
Revenue
Cost
13.60 x
-5.80 x
>
7.80 x
7.80
>
x
>
5.80 x + 120
-5.80 x
120
7.80
15.3846
Frank must sell at least
16 frames in order for
his revenue to be
greater than his costs.
6
2
Dropping down an altitude
forms a 30o/60o/90o triangle.
6
8
=
9
n
6n = 72
n = 12
2 + 2(3)
8
2(2) + 3
7
(2)2 + (3)2
13
(2 + 3)2
25
Often times, the best way to solve a problem like this is to pick
an even number and an odd number and simply try them out.
Let’s make x = 2 and y = 3.
We’ll round the values off
as we go…
Sun = 800
Mon = 350
Tue = 400
Wed = 350
Thur = 300
Fri = 400
Sat = 900
TOTAL = 3500
3500 customers
7 days
= 500 each day
This is a volume problem.
V = (length)(width)(height)
V = (22)(9)(8)
V = 1584 in3
BE CAREFUL!
This is not our final answer…
…and it happens to be a choice.
DON’T BE FOOLED!
We need to take ¾ of 1584.
1188 in3
When an object travels
at a constant rate, the
graph will always be a
straight line.
The 34 employees with the lower salaries
would be better off with the $500 raise.
The 30 employees with the higher
salaries would be better off with
the 2% raise.
If these employees
voted, the $500
raise would be the
likely winner.
To figure the 2% raise,
multiply the current salary
by 1.02
Let’s compare both
situations and see what
the new salaries would be:
New Salaries
$500 raise
2% raise
$19,000
$20,800
$24,600
$31,500
$42,500
$58,500
$71,500
$18,870
$20,706
$24,582
$31,620
$42,840
$59,160
$72,420
$18,500 * 1.02 = $18,870
$20,300 * 1.02 = $20,706
and so on…
We’ll draw a “line of best fit”
through the data points.
Since the line has a positive
slope, it’s obvious that the
population is not going to
decline or stay the same.
15
It’s unlikely that it will get above
120,000 in the next 10 years
when it’s not even above 50,000
during the first 10 years.
If we extend the line out,
you can see from the
graph that this is the
obvious choice.
OPP
Starting from the
shaded angle, label the
3 sides of the triangle:
HYP
ADJ
Since it’s a trig
problem, we’ll be using
SOH CAH TOA
The sides we’re dealing with are the
OPPOSITE and the ADJACENT, so
we’ll be using the TANGENT.
tangent =
opposite
adjacent
=
4
x
n =
687.5
3
n = 229.16666
Here are my estimates:
Superior = 31,000
Michigan = 22,000
Huron = 23,000
Erie = 10,000
Ontario = 8,000
Total = 94,000
If R and T are both midpoints,
then SR = 14 and ST = 12.
14
12
These 2 triangles are similar.
The orange triangle has sides
which are twice as long as
14
the yellow triangle. Using
12
this scale factor, the bottom
side of the yellow one is 14.
14
28
24
14 + 14 + 12 = 40
28
The final coordinates of the kite will be
P”(1, 3), Q”(2, 4), R”(1, 7), and S”(0, 4).
Some students may
choose not to use a
graph. Here’s what
they’d need to do:
P(-2, -1)
Q(-1, -2)
R(-2, -5)
S(-3, -2).
Reflecting the graph over the x-axis simply
changes the signs on the y-coordinates.
P’(-2, 1)
Q’(-1, 2)
R’(-2, 5)
S’(-3, 2).
Translating the graph 3 units right and 2 units up requires us
to add 3 to each x-coordinate and 2 to each y-coordinate.
P”(1, 3)
Q”(2, 4)
R”(1, 7)
S”(0, 4).
The final coordinates of the kite will be
P”(1, 3), Q”(2, 4), R”(1, 7), and S”(0, 4).
2
n -
w2
q
2/3
Do the
exponents
first.
1/9 -
36
2/3
Dividing by 2/3
is the same as
multiplying by 3/2.
1/9
54
2
(1/3) -
-
(-6)2
=
8
-53 9
Probability =
Probability =
Hispanic males
Total males
76,660
5,215,573
Probability = 0.0146982891
day #1
60 MPH
x 9 hours
540 miles
traveled
1244 miles total
- 540 miles on day #1
704 miles to go
day #2
704 miles
11 hours
=
64 MPH average
This presentation brought to you by
Mr. Jeff Luce
BBHHS Mathematics Dept.

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