AP Ch 8 Bonding (2005)

Ch. 8 Chemical Bonding
•Chemical bonds hold atoms together.
•There are 3 types of chemical bonds:
-Ionic bonds (electrostatic forces that hold ions
-Example: Na+Cl-, K+Br-
-Covalent bonds (result from sharing electrons
between atoms…)
-Example: H2, NH3
-Metallic bonds (refers to metal nuclei floating in a
sea of electrons…)
-Example: copper, gold
Lewis Symbols: Electron dots
•Valence Electrons: outer-most electrons
–determined by the “Group A #” from the periodic table
–Exceptions: d or f-block = 2 valence electrons & Helium =2 e-
Octet Rule
•Atoms often gain or lose or share electrons to fill their
valence shell with 8 electrons to achieve a noble gas
–Exceptions: * Hydrogen needs only 2 e- to be filled.
* Some nonmetals can have more or less than 8.
Ionic Bonding
•Ionic bonds—transfer of electrons
- Form between an element of low ionization energy (not
much energy required to pull off an electron) and an element
of high electron affinity (lots of energy is released when an
electron is added to its outer shell).
- Usually form between a metal and a nonmetal.
Ionic Bonding Energies
• Consider the reaction between sodium and chlorine:
Na(s) + ½Cl2(g)  NaCl(s) ∆Hºf = –410.9 kJ/mol
- The reaction is violently exothermic.
- We infer that the NaCl is more stable than its
constituent elements.
• Here’s another way to look at the energy of ionic bond formation:
–Sodium loses 1 electron…Na  Na+ + 1 e– Chlorine gains l electron…Cl + 1 e-  Cl– NaCl forms… Na+ + Cl-  [Na+][ Cl-]
Requires 5.1 eV of energy
Releases 3.6 eV of energy
Releases 5.2 eV of energy
[1 eV (electron volt) = 1.602 x 10-19 J]
•The energy released is greater than the energy required, therefore
the ionic bond forms… (∆Hf = - 3.7 eV)
Lattice Energy
• Lattice energy is the energy required to completely
separate a mole of a solid ionic compound into its
gaseous ions.
–Lattice energy increases as distance between the ions decreases.
–Lattice energy increases as charges on the ions increase.
•Metals lose electrons to form smaller (+) cations.
•Nonmetals gain e- to form larger (-) anions.
–The # of e- gained or lost depends on how many they need to
gain or lose to get to a noble gas configuration. Only then will
they become stable.
•Groups of atoms can have charges too. They are called
polyatomic ions.
–The atoms share electrons (covalent bonds) but the group
still has an overall charge.
Examples: [NH4+] , [CO3-2]
Covalent Bonds
•Atoms share electrons to fill their valence shell.
•Usually form between 2 nonmetals
–Lewis Structures: represent covalent bonds as 2 dots between the atoms
Cl Cl
- A line can also be used to represent 2 shared e-’s (or one covalent bond.)
Multiple Covalent Bonds
•Single bond = 2 electrons shared …(1 pair)
•Double bond= 4 electrons shared…(2 pairs)
•Triple bond= 6 electrons shared…(3 pairs)
Bond Lengths & Bond Strengths
•Single bonds are the longest and weakest covalent
•Triple are the shortest and strongest covalent bonds.
•Ionic bonds are much stronger than covalent bonds.
Bond Polarity
•Bond polarity helps to describe the sharing of the
electrons between atoms. There are 3 possibilities…
–Nonpolar covalent: equal sharing of the e- pair
–Polar covalent: unequal sharing of the e- pair
–Ionic: transfer of valence e- from the metal to the nonmetal
•A molecule that has one side slightly positive and one
side slightly negative is said to be a “dipole.”
•The positive end (or pole) in a polar bond is represented
+ and the negative pole -. Arrow can also show dipoles.
Bond Polarity & Electronegativity
(How can you tell what type of bond will form?)
•Electronegativity: describes an atom’s attraction to the epair in a bond…(It’s a number from 0 to 4.0)
•The difference between electronegativities indicate
whether a bond will be nonpolar, polar or ionic.
•There is no sharp distinction between bonding types.
•In General: Nonpolar = 0-0.4
Polar= 0.5-2.0
Ionic= Above 2.0
Lattice Energy and Polarity
Lattice energy increases as the electronegativity
between the atoms in an ionic compound increases
Rules For Drawing Lewis Structures
Rule 1) How many electrons are possible around an atom?
• For hydrogen, only 2 electrons are possible, therefore only one bond!
• Second row elements usually try to get 8 e-. Notable Exception: Boron
needs only 6.
• Third & Fourth Row usually have 8 e- but can expand to get 10 or more.
Rule 2) Drawing the Lewis Structure:
• First arrange the atoms around the central atom (usually the highest
electronegative one, but never hydrogen!)
• Count the total # of valence electrons in the molecule. If it is an ion, add 1
for each (-) charge or subtract 1 for each (+) charge.
• Distribute the electrons keeping Rule #1 in mind. If you have too many
electrons, look for double or triple bonds, or place the extras around the “3rd
or 4th row element.”
Rules For Drawing Lewis Structures
Rule 3) For Ionic Compounds:
• Indicate the charge on the ions
• Do not share the electrons, transfer them!
Rule 4) For odd-numbered valence electrons:
If you must cheat an element out of 8 e- and only give it 7, then cheat the
least electronegative element.
Rule 5) Resonance Structures:
• If there is more than one way to draw the Lewis structure, show them all.
Rule 6) Nature doesn’t know anything about Rules1-5.
• These are just models for us to use in order to represent bonding.
Resonance Structures:
• The ability to draw more than one “correct” Lewis structure.
Benzene (C6H6)
• The true structure for the molecule is somewhere “in between” the
resonance structures.
Formal Charge
• Formal Charge: The formal charge of an atom is the
charge that an atom (in a molecule) would have if all
of the atoms had the same electronegativity.
• To calculate formal charge:
(valence e- - # of bonds - lone pair e-)
Practice: Determine the formal charge on C and N.
C= 4 – 3 – 2 = -1
N= 5 – 3 – 2 = 0
Formal Charge
• The most stable Lewis structure has the smallest formal
charge on each atom and the most negative formal charge
on the most electronegative atoms.
• It is important to keep in mind that formal charges do
NOT represent REAL charges on atoms!
Strengths of Covalent Bonds
• The energy required to break a covalent bond is
called the bond dissociation enthalpy, D.
That is, for the Cl2 molecule, D(Cl-Cl) is given by
H for the reaction:
Cl2(g)  2Cl(g)
H = 242 kJ
When more than one bond is broken…
CH4(g)  C(g) + 4H(g)
H = 1660 kJ
…the bond enthalpy is a fraction of H for the
“atomization reaction”:
D(C-H) = ¼H = ¼(1660 kJ) = 415 kJ
Strengths of Covalent Bonds
The bond
enthalpy for a
given set of
atoms depends
on the rest of the
molecule of
which it is a part.
An average bond
enthalpy is
therefore shown.
The energy
released when a
bond forms is
just the (-) of the
value shown in
the table!
Using “D” to determine ∆H(rxn)
∆H(rxn) =  D(bonds broken) -  D(bonds formed)
•Practice Problem
CH4(g) + Cl2(g)  CH3Cl(g) + HCl(g)
H(rxn) = ?
-In this reaction one C-H bond and one Cl-Cl bond is broken
while one C-Cl bond and one H-Cl bond is formed.
So… ∆H(rxn) = [D(C-H) + D(Cl-Cl)] - [D(C-Cl) + D(H-Cl)]
= 413kJ + 242 kJ – 328 kJ – 431 kJ = – 104 kJ
•The overall reaction is exothermic which means that the bonds
formed are stronger than the bonds broken.
•The above result is consistent with Hess’s law.

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