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Anna Chang 10-1 / T2 Perpendicular bisector is a line that cuts a segment into two equal parts, it creates 90 degrees. Here’s a segment AB b/c n is the perpendicular bisector, then it creates a 90 degree angle N is the perpendicular bisector of segment AB A 90 degrees B n is the perpendicular bisector of the segmen AB ㄱ 90 degrees n is the perpendicular bisector of the segmen AB n is the perpendicular bisector of XY 90 degrees Q is the perpendicular bisector of OP 90 degrees If a point lies on the perpendicular bisector of a segment then it is equidistant from both of the endpoints of the segment. XA=XB Example 1 : AB and CB 1. AB=CB 2. 5z+23=6z+14 3. 9=1z 4. Z=9 5. 5(9)+23 AB=68 6.6(9)+14 CB=68 Find X X=24 Since l is perpendicular bisector of TU, W is the midpoint of TU. <TWV and <WUV are right angles by def. of perpendicular. Later WV=VW by reflexive property. VT=VU by CPCT So X=24 A point lies on the perpendicular bisector of a segment if and only if is equidistant from both of the sides