### 5-1 perpendicular and angle bisectors

```Anna Chang
10-1 / T2
Perpendicular bisector is a line
that cuts a segment into two equal
parts, it creates 90 degrees.
Here’s a segment AB
b/c n is the perpendicular
bisector, then it creates a 90
degree angle
N is the perpendicular bisector
of segment AB
A
90 degrees
B
n is the perpendicular bisector of the segmen AB
ㄱ
90
degrees
n is the perpendicular bisector of the segmen AB
n is the
perpendicular
bisector of XY
90
degrees
Q is the
perpendicular
bisector of OP
90
degrees
 If a point lies on the perpendicular
bisector of a segment then it is
equidistant from both of the
endpoints of the segment.
XA=XB
Example 1 :
AB and CB
1. AB=CB
2. 5z+23=6z+14
3. 9=1z
4. Z=9
5. 5(9)+23
AB=68
6.6(9)+14
CB=68
Find X
X=24
Since l is
perpendicular
bisector of TU, W is
the midpoint of TU.
<TWV and <WUV
are right angles by
def. of
perpendicular. Later
WV=VW by reflexive
property. VT=VU by
CPCT
So
X=24
A point lies on the perpendicular
bisector of a segment if and only if is
equidistant from both of the sides
```